Wie oft bin ich am flop ahead gegen AA mit...?

[Wi11i]

Hier ein Beitrag betreffend Pokerstove benützung und schauen wie oft man an einem flop ahead ist gegen z.b. AA.


"what i'm talking about with the "dog on the flop" is:
you're ~6.5% ahead vs AA on any random flop... You'll still get outdrawn... only thing of interest is "how many times am i ahead when I see the flop" (which means being ahead vs AA with 2 pairs for example).

Some examples:
When you hit 2 pairs, this counts to the times where you're ahead, when you hit 1 pair, you're behind. You hit a OESD, you're behind. You hit a pair and an OESD - still counts as being behind. So only thing that counts is when you could SD your hand right on the flop and the one with the better hand wins it right there.

How to get that %?
Just enter it in pokerstove. Use a board of 2 cards which does not connect to JT (let's call it virtual board). It can connect to AA as AA does not need cards to win in more than 90% of the times. So if something connects to the virtual board, like in this case 235, it won't matter, as JT is gonna lose on that board anyways. Then you can choose whether to say the cards of the virtual board are dead (so JT is not behind on a board where JT made 2 pairs, but AA hit 2 pairs too because of one of cards of our virtual board) or to keep the cards alive so we don't help JT too much (if 8 cards of the deck are missing, which don't help JT it's gonna falsify the result too)

like

Board: 6s 4d
Dead: 6c 6d 6h 4c 4h 4s

equity win tie pots won pots tied
Hand 0: 08.047% 07.11% 00.94% 702 93.00 { JcTh }
Hand 1: 91.953% 91.01% 00.94% 8992 93.00 { AdAs }

This isn't 100% accurate as 8 cards are missing of course, which would not have helped JTo (if a 4 or a 6 flops, odds are higher AA wins). So the final % is probably around 6-7%

I didn't know how to do that before... maybe you guys knew or is there a better way to find out how many times you dominate AA with ATC on the flop? "

update: ich denke es ist besser, die dead cards weg zu lassen. Die 8 karten geben JT einen grossen vorteil, wenn 2 karten fehlen gibt das JT immernoch einen vorteil, gleichzeitig auch AA wegen 2 pairs. Es ist also eher eine zwischenlösung